Remove quotes from subshell call in bash script
Always no quotes for $() statement. We don't need quotes to hold blanks in result: # i=$(echo 1 2 3) # echo $i 1 2 3 # These quotes can make something wrong in some case: # i=$(echo '!') # # i="$(echo '!')" -bash: !: event not found # No real problem for current code, only to use a better code style. Change-Id: I3c87987d3b992c8363ef236a04ae6e35c1315535 Signed-off-by: Zhao Lei <zhaolei@cn.fujitsu.com>
This commit is contained in:
parent
dcfc9336e7
commit
19378504b5
|
@ -24,7 +24,7 @@ pruner="git ls-files | grep -v \"$keep_pattern\" | git update-index --force-remo
|
|||
|
||||
roots=""
|
||||
for file in $files_to_keep; do
|
||||
file_root="$(git rev-list --reverse HEAD -- $file | head -n1)"
|
||||
file_root=$(git rev-list --reverse HEAD -- $file | head -n1)
|
||||
fail=0
|
||||
for root in $roots; do
|
||||
if git merge-base --is-ancestor $root $file_root; then
|
||||
|
|
Loading…
Reference in New Issue