65 lines
2.3 KiB
Python
65 lines
2.3 KiB
Python
# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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import datetime
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WEEKDAYS = {'Monday': 0, 'Tuesday': 1, 'Wednesday': 2, 'Thursday': 3,
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'Friday': 4, 'Saturday': 5, 'Sunday': 6}
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def next_weekday(ref_date, day):
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"""Return the date of the next meeting.
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:param ref_date: datetime object of meeting
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:param day: weekday the meeting is held on
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:returns: datetime object of the next meeting time
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"""
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weekday = WEEKDAYS[day]
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days_ahead = weekday - ref_date.weekday()
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if days_ahead <= 0: # target day already happened this week
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days_ahead += 7
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return ref_date + datetime.timedelta(days_ahead)
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def next_biweekly_meeting(current_date_time, day, meet_on_even=False):
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"""Calculate the next biweekly meeting.
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:param current_date_time: the current datetime object
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:param day: scheduled day of the meeting
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:param meet_on_even: True if meeting on even weeks and False if meeting
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on odd weeks
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:returns: datetime object of next meeting
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"""
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weekday = WEEKDAYS[day]
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first_day_of_mo = current_date_time.replace(day=1)
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day_of_week = first_day_of_mo.strftime("%w")
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adjustment = (8 - int(day_of_week)) % (7 - weekday)
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if meet_on_even:
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adjustment += 7
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next_meeting = first_day_of_mo + datetime.timedelta(adjustment)
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if current_date_time > next_meeting:
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next_meeting = next_meeting + datetime.timedelta(14)
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if current_date_time > next_meeting:
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current_date_time = current_date_time.replace(
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month=current_date_time.month + 1, day=1)
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first_wday_next_mo = next_weekday(current_date_time, weekday)
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if meet_on_even:
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next_meeting = first_wday_next_mo + datetime.timedelta(7)
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else:
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next_meeting = first_wday_next_mo
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return next_meeting
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