52 lines
1.8 KiB
Python
52 lines
1.8 KiB
Python
# Licensed under the Apache License, Version 2.0 (the "License"); you may
|
|
# not use this file except in compliance with the License. You may obtain
|
|
# a copy of the License at
|
|
#
|
|
# http://www.apache.org/licenses/LICENSE-2.0
|
|
#
|
|
# Unless required by applicable law or agreed to in writing, software
|
|
# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
|
|
# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
|
|
# License for the specific language governing permissions and limitations
|
|
# under the License.
|
|
|
|
import logging
|
|
|
|
from keystoneclient.auth.identity import v2 as v2_auth
|
|
from keystoneclient.auth.identity import v3 as v3_auth
|
|
|
|
from openstack_auth.plugin import base
|
|
from openstack_auth import utils
|
|
|
|
LOG = logging.getLogger(__name__)
|
|
|
|
__all__ = ['PasswordPlugin']
|
|
|
|
|
|
class PasswordPlugin(base.BasePlugin):
|
|
"""Authenticate against keystone given a username and password.
|
|
|
|
This is the default login mechanism. Given a username and password inputted
|
|
from a login form returns a v2 or v3 keystone Password plugin for
|
|
authentication.
|
|
"""
|
|
|
|
def get_plugin(self, auth_url=None, username=None, password=None,
|
|
user_domain_name=None, **kwargs):
|
|
if not all((auth_url, username, password)):
|
|
return None
|
|
|
|
LOG.debug('Attempting to authenticate for %s', username)
|
|
|
|
if utils.get_keystone_version() >= 3:
|
|
return v3_auth.Password(auth_url=auth_url,
|
|
username=username,
|
|
password=password,
|
|
user_domain_name=user_domain_name,
|
|
unscoped=True)
|
|
|
|
else:
|
|
return v2_auth.Password(auth_url=auth_url,
|
|
username=username,
|
|
password=password)
|