Remove quotes from subshell call in bash script
Always no quotes for $() statement. We don't need quotes to hold blanks in result: # i=$(echo 1 2 3) # echo $i 1 2 3 # These quotes can make something wrong in some case: # i=$(echo '!') # # i="$(echo '!')" -bash: !: event not found # No real problem for current code, only to use a better code style. Change-Id: I0f43bb936f956c99603dc15aaad9db851ecf0acd Signed-off-by: Zhao Lei <zhaolei@cn.fujitsu.com>
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@ -12,7 +12,7 @@ if [ ! -d "$PWD/.diagram-tools" ]; then
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git clone "https://github.com/vidarh/diagram-tools.git" "$PWD/.diagram-tools"
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fi
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script_dir="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
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script_dir=$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )
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img_dir="$script_dir/../doc/source/img"
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echo "---- Updating task state diagram ----"
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